CoolFace
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FPEvalDataset/LeetCodeProblem

sourceHugging Faceupdated 8mo agoView on Hugging Face
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1{2    "id": 3744,3    "name": "minimum_operations_to_make_array_elements_zero",4    "difficulty": "Hard",5    "link": "https://leetcode.com/problems/minimum-operations-to-make-array-elements-zero/",6    "date": "2025-03-16 00:00:00",7    "task_description": "You are given a 2D array `queries`, where `queries[i]` is of the form `[l, r]`. Each `queries[i]` defines an array of integers `nums` consisting of elements ranging from `l` to `r`, both **inclusive**. In one operation, you can: Select two integers `a` and `b` from the array. Replace them with `floor(a / 4)` and `floor(b / 4)`. Your task is to determine the **minimum** number of operations required to reduce all elements of the array to zero for each query. Return the sum of the results for all queries. **Example 1:** **Input:** queries = [[1,2],[2,4]] **Output:** 3 **Explanation:** For `queries[0]`: The initial array is `nums = [1, 2]`. In the first operation, select `nums[0]` and `nums[1]`. The array becomes `[0, 0]`. The minimum number of operations required is 1. For `queries[1]`: The initial array is `nums = [2, 3, 4]`. In the first operation, select `nums[0]` and `nums[2]`. The array becomes `[0, 3, 1]`. In the second operation, select `nums[1]` and `nums[2]`. The array becomes `[0, 0, 0]`. The minimum number of operations required is 2. The output is `1 + 2 = 3`. **Example 2:** **Input:** queries = [[2,6]] **Output:** 4 **Explanation:** For `queries[0]`: The initial array is `nums = [2, 3, 4, 5, 6]`. In the first operation, select `nums[0]` and `nums[3]`. The array becomes `[0, 3, 4, 1, 6]`. In the second operation, select `nums[2]` and `nums[4]`. The array becomes `[0, 3, 1, 1, 1]`. In the third operation, select `nums[1]` and `nums[2]`. The array becomes `[0, 0, 0, 1, 1]`. In the fourth operation, select `nums[3]` and `nums[4]`. The array becomes `[0, 0, 0, 0, 0]`. The minimum number of operations required is 4. The output is 4. **Constraints:** `1 <= queries.length <= 105` `queries[i].length == 2` `queries[i] == [l, r]` `1 <= l < r <= 109`",8    "public_test_cases": [9        {10            "label": "Example 1",11            "input": "queries = [[1,2],[2,4]]",12            "output": "3 "13        },14        {15            "label": "Example 2",16            "input": "queries = [[2,6]]",17            "output": "4 "18        }19    ],20    "private_test_cases": [],21    "haskell_template": "minOperations :: [[Int]] -> Int\nminOperations queries ",22    "ocaml_template": "let minOperations (queries: int list list) : int =  ",23    "scala_template": "def minOperations(queries: List[List[Int]]): Int = { \n    \n}",24    "java_template": "class Solution {\n    public long minOperations(int[][] queries) {\n        \n    }\n}",25    "python_template": "class Solution(object):\n    def minOperations(self, queries):\n        \"\"\"\n        :type queries: List[List[int]]\n        :rtype: int\n        \"\"\"\n        "26}