reshinthadith/CodeGen-Diversity
0
1,PC1,PC2,labels,values,prompts,prob_index20,3.5042703,0.005008956,embd_sc-3b-release_humaneval,"for i in range(len(numbers)):3 for j in range(i + 1, len(numbers)):4 if abs(numbers[i] - numbers[j]) < threshold:5 return True6 return False","from typing import List7 8 9def has_close_elements(numbers: List[float], threshold: float) -> bool:10 """""" Check if in given list of numbers, are any two numbers closer to each other than11 given threshold.12 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)13 False14 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)15 True16 """"""17",0181,3.6125972,-0.12634973,embd_sc-3b-release_humaneval,"for i in range(len(numbers) - 1):19 for j in range(i + 1, len(numbers)):20 if abs(numbers[i] - numbers[j]) < threshold:21 return True22 return False","from typing import List23 24 25def has_close_elements(numbers: List[float], threshold: float) -> bool:26 """""" Check if in given list of numbers, are any two numbers closer to each other than27 given threshold.28 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)29 False30 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)31 True32 """"""33",0342,-2.259092,-0.26904663,embd_ds-6.7b-release_humaneval,"numbers.sort()35 for i in range(len(numbers) - 1):36 if numbers[i+1] - numbers[i] < threshold:37 return True38 return False","from typing import List39 40 41def separate_paren_groups(paren_string: str) -> List[str]:42 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to43 separate those group into separate strings and return the list of those.44 Separate groups are balanced (each open brace is properly closed) and not nested within each other45 Ignore any spaces in the input string.46 >>> separate_paren_groups('( ) (( )) (( )( ))')47 ['()', '(())', '(()())']48 """"""49",0503,-2.1540294,-0.93258446,embd_ds-6.7b-release_humaneval,"numbers.sort()51 for i in range(len(numbers) - 1):52 if numbers[i+1] - numbers[i] < threshold:53 return True54 return False","from typing import List55 56 57def separate_paren_groups(paren_string: str) -> List[str]:58 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to59 separate those group into separate strings and return the list of those.60 Separate groups are balanced (each open brace is properly closed) and not nested within each other61 Ignore any spaces in the input string.62 >>> separate_paren_groups('( ) (( )) (( )( ))')63 ['()', '(())', '(()())']64 """"""65",0664,-2.1540294,-0.9325852,embd_ds-6.7b-release_humaneval,"numbers.sort()67 for i in range(1, len(numbers)):68 if numbers[i] - numbers[i - 1] < threshold:69 return True70 return False","from typing import List71 72 73def separate_paren_groups(paren_string: str) -> List[str]:74 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to75 separate those group into separate strings and return the list of those.76 Separate groups are balanced (each open brace is properly closed) and not nested within each other77 Ignore any spaces in the input string.78 >>> separate_paren_groups('( ) (( )) (( )( ))')79 ['()', '(())', '(()())']80 """"""81",0825,-1.282084,1.5457939,embd_ds-1.3b-inst-release_humaneval,"numbers.sort()83 for i in range(1, len(numbers)):84 if abs(numbers[i] - numbers[i-1]) < threshold:85 return True86 return False","87 88def truncate_number(number: float) -> float:89 """""" Given a positive floating point number, it can be decomposed into90 and integer part (largest integer smaller than given number) and decimals91 (leftover part always smaller than 1).92 93 Return the decimal part of the number.94 >>> truncate_number(3.5)95 0.596 """"""97",0986,3.6125968,-0.12634969,embd_ds-1.3b-inst-release_humaneval,"numbers.sort()99 for i in range(1, len(numbers)):100 if numbers[i] - numbers[i-1] < threshold:101 return True102 return False","103 104def truncate_number(number: float) -> float:105 """""" Given a positive floating point number, it can be decomposed into106 and integer part (largest integer smaller than given number) and decimals107 (leftover part always smaller than 1).108 109 Return the decimal part of the number.110 >>> truncate_number(3.5)111 0.5112 """"""113",01147,-1.7430475,1.5618639,embd_ds-1.3b-inst-release_humaneval,"for i in range(len(numbers)):115 for j in range(i + 1, len(numbers)):116 if abs(numbers[i] - numbers[j]) < threshold:117 return True118 return False","119 120def truncate_number(number: float) -> float:121 """""" Given a positive floating point number, it can be decomposed into122 and integer part (largest integer smaller than given number) and decimals123 (leftover part always smaller than 1).124 125 Return the decimal part of the number.126 >>> truncate_number(3.5)127 0.5128 """"""129",01308,-2.2590923,-0.26904663,embd_ds-1.3b-inst-release_humaneval,"numbers.sort()131 for i in range(len(numbers) - 1):132 if abs(numbers[i] - numbers[i + 1]) < threshold:133 return True134 return False","135 136def truncate_number(number: float) -> float:137 """""" Given a positive floating point number, it can be decomposed into138 and integer part (largest integer smaller than given number) and decimals139 (leftover part always smaller than 1).140 141 Return the decimal part of the number.142 >>> truncate_number(3.5)143 0.5144 """"""145",01469,-2.4906874,-0.33035377,embd_ds-1.3b-inst-release_humaneval,"numbers.sort()147 for i in range(1, len(numbers)):148 if numbers[i] - numbers[i - 1] < threshold:149 return True150 return False","151 152def truncate_number(number: float) -> float:153 """""" Given a positive floating point number, it can be decomposed into154 and integer part (largest integer smaller than given number) and decimals155 (leftover part always smaller than 1).156 157 Return the decimal part of the number.158 >>> truncate_number(3.5)159 0.5160 """"""161",016210,3.6125972,-0.12634969,embd_ds-33b-humaneval,"for i in range(len(numbers)):163 for j in range(i + 1, len(numbers)):164 if abs(numbers[i] - numbers[j]) < threshold:165 return True166 return False","from typing import List167 168 169def below_zero(operations: List[int]) -> bool:170 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with171 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and172 at that point function should return True. Otherwise it should return False.173 >>> below_zero([1, 2, 3])174 False175 >>> below_zero([1, 2, -4, 5])176 True177 """"""178",01790,1.0781486,-2.3467503,embd_sc-3b-release_humaneval,"paren_groups = []180 paren_stack = []181 for paren in paren_string:182 if paren == '(':183 paren_stack.append(paren)184 elif paren == ')':185 if len(paren_stack) == 0:186 raise ValueError('Unbalanced parentheses')187 paren_stack.pop()188 if len(paren_stack) == 0:189 paren_groups.append(paren_string[paren_string.index(paren) + 1 : paren_string.index(paren) + 1 + len(paren_stack) * 2])190 return paren_groups","from typing import List191 192 193def has_close_elements(numbers: List[float], threshold: float) -> bool:194 """""" Check if in given list of numbers, are any two numbers closer to each other than195 given threshold.196 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)197 False198 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)199 True200 """"""201",12021,1.0983976,-2.2828574,embd_sc-3b-release_humaneval,"paren_string = paren_string.strip()203 paren_list = []204 paren_stack = []205 for paren in paren_string:206 if paren == '(':207 paren_stack.append(paren)208 elif paren == ')':209 if len(paren_stack) == 0:210 raise ValueError(""Unbalanced parentheses"")211 paren_stack.pop()212 if len(paren_stack) == 0:213 paren_list.append(paren_string[len(paren_list):paren_string.index(paren)])214 if len(paren_stack) != 0:215 raise ValueError(""Unbalanced parentheses"")216 return paren_list","from typing import List217 218 219def has_close_elements(numbers: List[float], threshold: float) -> bool:220 """""" Check if in given list of numbers, are any two numbers closer to each other than221 given threshold.222 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)223 False224 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)225 True226 """"""227",12282,-1.6682487,0.7224472,embd_sc-3b-release_humaneval,"paren_groups = []229 paren_stack = []230 for paren in paren_string:231 if paren == '(':232 paren_stack.append(paren)233 elif paren == ')':234 if not paren_stack:235 raise ValueError('Unbalanced parentheses')236 paren_stack.pop()237 if not paren_stack:238 paren_groups.append(''.join(paren_stack))239 if paren_stack:240 raise ValueError('Unbalanced parentheses')241 return paren_groups","from typing import List242 243 244def has_close_elements(numbers: List[float], threshold: float) -> bool:245 """""" Check if in given list of numbers, are any two numbers closer to each other than246 given threshold.247 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)248 False249 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)250 True251 """"""252",12533,-1.579033,0.3728004,embd_sc-3b-release_humaneval,"paren_groups = []254 paren_stack = []255 for paren in paren_string:256 if paren == '(':257 paren_stack.append(paren)258 elif paren == ')':259 if not paren_stack:260 raise ValueError(""Unbalanced parentheses"")261 if paren_stack[-1] == '(':262 paren_stack.pop()263 else:264 raise ValueError(""Unbalanced parentheses"")265 else:266 raise ValueError(""Invalid character"")267 if paren_stack:268 raise ValueError(""Unbalanced parentheses"")269 paren_groups = [paren_string[i:j + 1] for i, j in zip(range(len(paren_string)),270 range(len(paren_string), 0, -1)) if paren_string[i] == '(']271 return paren_groups","from typing import List272 273 274def has_close_elements(numbers: List[float], threshold: float) -> bool:275 """""" Check if in given list of numbers, are any two numbers closer to each other than276 given threshold.277 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)278 False279 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)280 True281 """"""282",12834,0.8683566,-2.3214898,embd_sc-3b-release_humaneval,"paren_list = []284 paren_stack = []285 for paren in paren_string:286 if paren == '(':287 paren_stack.append(paren)288 elif paren == ')':289 if len(paren_stack) == 0:290 raise ValueError(""Unbalanced parentheses"")291 if paren_stack[-1] == '(':292 paren_stack.pop()293 else:294 raise ValueError(""Unbalanced parentheses"")295 else:296 raise ValueError(""Invalid character"")297 if len(paren_stack) != 0:298 raise ValueError(""Unbalanced parentheses"")299 paren_list = [paren_string[i:j+1] for i, j in zip(range(len(paren_string)), range(1, len(paren_string)+1)) if paren_string[i] == '(' and paren_string[j] == ')']300 return paren_list","from typing import List301 302 303def has_close_elements(numbers: List[float], threshold: float) -> bool:304 """""" Check if in given list of numbers, are any two numbers closer to each other than305 given threshold.306 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)307 False308 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)309 True310 """"""311",13125,-1.7272563,0.7519353,embd_sc-3b-release_humaneval,"paren_groups = []313 paren_stack = []314 for paren in paren_string:315 if paren == '(':316 paren_stack.append(paren)317 elif paren == ')':318 if not paren_stack:319 raise ValueError('Unbalanced parentheses')320 paren_stack.pop()321 if not paren_stack:322 paren_groups.append(paren_string[len(paren_groups):len(paren_string) - len(paren_stack)])323 if paren_stack:324 raise ValueError('Unbalanced parentheses')325 return paren_groups","from typing import List326 327 328def has_close_elements(numbers: List[float], threshold: float) -> bool:329 """""" Check if in given list of numbers, are any two numbers closer to each other than330 given threshold.331 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)332 False333 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)334 True335 """"""336",13376,-1.7914414,0.80501276,embd_sc-3b-release_humaneval,"paren_string = paren_string.strip()338 paren_groups = []339 paren_stack = []340 for char in paren_string:341 if char == '(':342 paren_stack.append(char)343 elif char == ')':344 if not paren_stack:345 raise ValueError('Unbalanced parentheses')346 paren_stack.pop()347 if not paren_stack:348 paren_groups.append(paren_string[len(paren_groups) * 2:len(paren_stack) * 2])349 if paren_stack:350 raise ValueError('Unbalanced parentheses')351 return paren_groups","from typing import List352 353 354def has_close_elements(numbers: List[float], threshold: float) -> bool:355 """""" Check if in given list of numbers, are any two numbers closer to each other than356 given threshold.357 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)358 False359 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)360 True361 """"""362",13637,-1.6077102,0.56224316,embd_sc-3b-release_humaneval,"paren_stack = []364 paren_list = []365 for paren in paren_string:366 if paren == '(':367 paren_stack.append(paren)368 elif paren == ')':369 if len(paren_stack) == 0:370 raise ValueError('Unbalanced parentheses')371 paren_stack.pop()372 else:373 raise ValueError('Invalid input')374 if len(paren_stack) != 0:375 raise ValueError('Unbalanced parentheses')376 paren_list = [paren_string[i:j+1] for i, j in zip(range(len(paren_string)), range(len(paren_string), 0, -1))]377 return paren_list","from typing import List378 379 380def has_close_elements(numbers: List[float], threshold: float) -> bool:381 """""" Check if in given list of numbers, are any two numbers closer to each other than382 given threshold.383 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)384 False385 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)386 True387 """"""388",13898,-1.8601445,0.6414156,embd_sc-3b-release_humaneval,"paren_list = []390 paren_stack = []391 for paren in paren_string:392 if paren == '(':393 paren_stack.append(paren)394 elif paren == ')':395 if len(paren_stack) > 0:396 paren_stack.pop()397 else:398 paren_list.append(')')399 else:400 paren_list.append(paren)401 if len(paren_stack) > 0:402 paren_list.append('(')403 return paren_list","from typing import List404 405 406def has_close_elements(numbers: List[float], threshold: float) -> bool:407 """""" Check if in given list of numbers, are any two numbers closer to each other than408 given threshold.409 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)410 False411 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)412 True413 """"""414",14159,1.6540036,-2.4872236,embd_sc-3b-release_humaneval,"paren_groups = []416 paren_stack = []417 for paren in paren_string:418 if paren == '(':419 paren_stack.append(paren)420 elif paren == ')':421 if len(paren_stack) == 0:422 raise ValueError('Unbalanced parentheses')423 else:424 paren_stack.pop()425 else:426 raise ValueError('Invalid input')427 if len(paren_stack) != 0:428 raise ValueError('Unbalanced parentheses')429 else:430 paren_groups = [paren_string[i:j+1] for i, j in zip(range(len(paren_string)), range(len(paren_string), 0, -1))]431 return paren_groups","from typing import List432 433 434def has_close_elements(numbers: List[float], threshold: float) -> bool:435 """""" Check if in given list of numbers, are any two numbers closer to each other than436 given threshold.437 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)438 False439 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)440 True441 """"""442",144310,-1.08243,-0.16148709,embd_ds-6.7b-release_humaneval,"paren_string = paren_string.replace("" "", """")444 stack = []445 result = []446 temp = """"447 for char in paren_string:448 if char == ""("":449 stack.append(char)450 if temp != """":451 temp += char452 elif char == "")"":453 stack.pop()454 temp += char455 if not stack:456 result.append(temp)457 temp = """"458 return result","from typing import List459 460 461def separate_paren_groups(paren_string: str) -> List[str]:462 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to463 separate those group into separate strings and return the list of those.464 Separate groups are balanced (each open brace is properly closed) and not nested within each other465 Ignore any spaces in the input string.466 >>> separate_paren_groups('( ) (( )) (( )( ))')467 ['()', '(())', '(()())']468 """"""469",147011,0.71278983,-2.873535,embd_ds-6.7b-release_humaneval,"groups = []471 stack = []472 start = 0473 for i, char in enumerate(paren_string):474 if char == '(':475 if not stack:476 start = i477 stack.append(char)478 elif char == ')':479 stack.pop()480 if not stack:481 groups.append(paren_string[start:i+1].replace(' ', ''))482 return groups","from typing import List483 484 485def separate_paren_groups(paren_string: str) -> List[str]:486 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to487 separate those group into separate strings and return the list of those.488 Separate groups are balanced (each open brace is properly closed) and not nested within each other489 Ignore any spaces in the input string.490 >>> separate_paren_groups('( ) (( )) (( )( ))')491 ['()', '(())', '(()())']492 """"""493",149412,-1.724142,1.0747672,embd_ds-6.7b-release_humaneval,"groups = []495 stack = []496 start = 0497 for i, char in enumerate(paren_string):498 if char == '(':499 if not stack:500 start = i501 stack.append(char)502 elif char == ')':503 stack.pop()504 if not stack:505 groups.append(paren_string[start:i+1].replace(' ', ''))506 return groups","from typing import List507 508 509def separate_paren_groups(paren_string: str) -> List[str]:510 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to511 separate those group into separate strings and return the list of those.512 Separate groups are balanced (each open brace is properly closed) and not nested within each other513 Ignore any spaces in the input string.514 >>> separate_paren_groups('( ) (( )) (( )( ))')515 ['()', '(())', '(()())']516 """"""517",151813,0.99506915,-3.6535072,embd_ds-6.7b-release_humaneval,"paren_string = paren_string.replace("" "", """")519 stack = []520 result = []521 temp = """"522 for char in paren_string:523 if char == '(':524 if temp:525 stack.append(temp)526 temp = """"527 stack.append(char)528 elif char == ')':529 stack.append(char)530 while stack[-2] != '(':531 top = stack.pop()532 temp = top + temp533 stack.pop()534 temp = ""("" + temp + "")""535 if len(stack) >= 2 and stack[-2] == '(' and stack[-1] == ')':536 result.append(temp)537 temp = """"538 stack = stack[:-2]539 if stack:540 temp = stack.pop()541 return result","from typing import List542 543 544def separate_paren_groups(paren_string: str) -> List[str]:545 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to546 separate those group into separate strings and return the list of those.547 Separate groups are balanced (each open brace is properly closed) and not nested within each other548 Ignore any spaces in the input string.549 >>> separate_paren_groups('( ) (( )) (( )( ))')550 ['()', '(())', '(()())']551 """"""552",155314,-2.1181016,2.1155057,embd_ds-6.7b-release_humaneval,"groups = []554 stack = []555 start = 0556 for i, char in enumerate(paren_string):557 if char == '(':558 if not stack:559 start = i560 stack.append(char)561 elif char == ')':562 stack.pop()563 if not stack:564 groups.append(paren_string[start:i+1])565 return [group.replace(' ', '') for group in groups]","from typing import List566 567 568def separate_paren_groups(paren_string: str) -> List[str]:569 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to570 separate those group into separate strings and return the list of those.571 Separate groups are balanced (each open brace is properly closed) and not nested within each other572 Ignore any spaces in the input string.573 >>> separate_paren_groups('( ) (( )) (( )( ))')574 ['()', '(())', '(()())']575 """"""576",157715,-1.724142,1.0747672,embd_ds-6.7b-release_humaneval,"# Initialize an empty list to store the separate groups578 separate_groups = []579 # Initialize an empty string to store the current group580 current_group = """"581 # Initialize a counter to track the number of open parentheses582 open_count = 0583 # Iterate over each character in the input string584 for char in paren_string:585 # Ignore spaces586 if char == "" "":587 continue588 # Add the character to the current group589 current_group += char590 # If the character is an open parenthesis, increment the counter591 if char == ""("":592 open_count += 1593 # If the character is a close parenthesis, decrement the counter594 elif char == "")"":595 open_count -= 1596 # If the counter reaches zero, we've found a separate group597 if open_count == 0:598 separate_groups.append(current_group)599 current_group = """"600 # Return the list of separate groups601 return separate_groups","from typing import List602 603 604def separate_paren_groups(paren_string: str) -> List[str]:605 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to606 separate those group into separate strings and return the list of those.607 Separate groups are balanced (each open brace is properly closed) and not nested within each other608 Ignore any spaces in the input string.609 >>> separate_paren_groups('( ) (( )) (( )( ))')610 ['()', '(())', '(()())']611 """"""612",161316,1.2114801,-3.5373847,embd_ds-6.7b-release_humaneval,"result = []614 stack = []615 start = 0616 for i, c in enumerate(paren_string):617 if c == '(':618 if not stack:619 start = i620 stack.append(c)621 elif c == ')':622 stack.pop()623 if not stack:624 result.append(paren_string[start:i+1].replace(' ', ''))625 return result","from typing import List626 627 628def separate_paren_groups(paren_string: str) -> List[str]:629 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to630 separate those group into separate strings and return the list of those.631 Separate groups are balanced (each open brace is properly closed) and not nested within each other632 Ignore any spaces in the input string.633 >>> separate_paren_groups('( ) (( )) (( )( ))')634 ['()', '(())', '(()())']635 """"""636",163717,-2.1902993,2.7116406,embd_ds-1.3b-inst-release_humaneval,"groups = []638 start = 0639 while start < len(paren_string):640 group = ''641 count = 0642 for i in range(start, len(paren_string)):643 if paren_string[i] == '(':644 count += 1645 elif paren_string[i] == ')':646 count -= 1647 if count == 0:648 group += paren_string[start:i+1]649 start = i+1650 break651 groups.append(group)652 return groups","653 654def truncate_number(number: float) -> float:655 """""" Given a positive floating point number, it can be decomposed into656 and integer part (largest integer smaller than given number) and decimals657 (leftover part always smaller than 1).658 659 Return the decimal part of the number.660 >>> truncate_number(3.5)661 0.5662 """"""663",166418,-2.0058916,2.7994738,embd_ds-1.3b-inst-release_humaneval,"groups = []665 start = 0666 while start < len(paren_string):667 count = 0668 for i in range(start, len(paren_string)):669 if paren_string[i] == '(':670 count += 1671 elif paren_string[i] == ')':672 count -= 1673 if count == 0:674 groups.append(paren_string[start:i+1])675 start = i+1676 break677 return groups","678 679def truncate_number(number: float) -> float:680 """""" Given a positive floating point number, it can be decomposed into681 and integer part (largest integer smaller than given number) and decimals682 (leftover part always smaller than 1).683 684 Return the decimal part of the number.685 >>> truncate_number(3.5)686 0.5687 """"""688",168919,1.4265298,-3.6675744,embd_ds-1.3b-inst-release_humaneval,"groups = []690 stack = []691 start = 0692 for i, char in enumerate(paren_string):693 if char == '(':694 if stack:695 start = i696 stack.append(char)697 elif char == ')':698 stack.pop()699 if not stack:700 groups.append(paren_string[start:i+1])701 return groups","702 703def truncate_number(number: float) -> float:704 """""" Given a positive floating point number, it can be decomposed into705 and integer part (largest integer smaller than given number) and decimals706 (leftover part always smaller than 1).707 708 Return the decimal part of the number.709 >>> truncate_number(3.5)710 0.5711 """"""712",171320,-1.7659657,1.3360289,embd_ds-1.3b-inst-release_humaneval,"result = []714 stack = []715 temp = ''716 for char in paren_string:717 if char == ' ':718 continue719 if char == '(':720 stack.append(char)721 temp += char722 elif char == ')':723 stack.append(char)724 temp += char725 if len(stack) == 1:726 result.append(temp)727 temp = ''728 else:729 temp += ' '730 return result","731 732def truncate_number(number: float) -> float:733 """""" Given a positive floating point number, it can be decomposed into734 and integer part (largest integer smaller than given number) and decimals735 (leftover part always smaller than 1).736 737 Return the decimal part of the number.738 >>> truncate_number(3.5)739 0.5740 """"""741",174221,1.4481704,-3.7042668,embd_ds-1.3b-inst-release_humaneval,"groups = []743 start = 0744 count = 0745 for i, char in enumerate(paren_string):746 if char == '(':747 count += 1748 elif char == ')':749 count -= 1750 if count == 0:751 groups.append(paren_string[start:i+1])752 start = i+1753 return groups","754 755def truncate_number(number: float) -> float:756 """""" Given a positive floating point number, it can be decomposed into757 and integer part (largest integer smaller than given number) and decimals758 (leftover part always smaller than 1).759 760 Return the decimal part of the number.761 >>> truncate_number(3.5)762 0.5763 """"""764",176522,-1.9698737,2.4738016,embd_ds-1.3b-inst-release_humaneval,"result = []766 stack = []767 temp = ''768 for char in paren_string:769 if char == ' ':770 continue771 if char == '(':772 stack.append(char)773 temp += char774 if char == ')':775 stack.append(char)776 temp += char777 if len(stack) == 1:778 result.append(temp)779 temp = ''780 else:781 stack.pop()782 return result","783 784def truncate_number(number: float) -> float:785 """""" Given a positive floating point number, it can be decomposed into786 and integer part (largest integer smaller than given number) and decimals787 (leftover part always smaller than 1).788 789 Return the decimal part of the number.790 >>> truncate_number(3.5)791 0.5792 """"""793",179423,-1.7659657,1.3360289,embd_ds-1.3b-inst-release_humaneval,"groups = []795 stack = []796 start = 0797 for i, char in enumerate(paren_string):798 if char == '(':799 if stack:800 start = i801 stack.append(char)802 elif char == ')':803 stack.pop()804 if not stack:805 groups.append(paren_string[start:i+1])806 return groups","807 808def truncate_number(number: float) -> float:809 """""" Given a positive floating point number, it can be decomposed into810 and integer part (largest integer smaller than given number) and decimals811 (leftover part always smaller than 1).812 813 Return the decimal part of the number.814 >>> truncate_number(3.5)815 0.5816 """"""817",181824,-1.3166589,2.4338064,embd_ds-33b-humaneval,"paren_string = paren_string.replace(' ', '')819 groups = []820 start = 0821 count = 0822 for i, char in enumerate(paren_string):823 if char == '(':824 count += 1825 elif char == ')':826 count -= 1827 if count == 0:828 groups.append(paren_string[start:i + 1])829 start = i + 1830 return groups","from typing import List831 832 833def below_zero(operations: List[int]) -> bool:834 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with835 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and836 at that point function should return True. Otherwise it should return False.837 >>> below_zero([1, 2, 3])838 False839 >>> below_zero([1, 2, -4, 5])840 True841 """"""842",184325,-2.0928082,2.3949971,embd_ds-33b-humaneval,"stack = []844 result = []845 for char in paren_string:846 if char == '(':847 stack.append(char)848 elif char == ')':849 stack.append(char)850 if len(stack) == 2:851 result.append(''.join(stack))852 stack = []853 return result","from typing import List854 855 856def below_zero(operations: List[int]) -> bool:857 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with858 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and859 at that point function should return True. Otherwise it should return False.860 >>> below_zero([1, 2, 3])861 False862 >>> below_zero([1, 2, -4, 5])863 True864 """"""865",186626,3.2716482,-0.97033006,embd_ds-33b-humaneval,"# Remove spaces from the string867 paren_string = paren_string.replace(' ', '')868 869 # Initialize variables870 groups = []871 group = ''872 open_count = 0873 874 # Iterate over the string875 for char in paren_string:876 if char == '(':877 open_count += 1878 elif char == ')':879 open_count -= 1880 group += char881 if open_count == 0:882 groups.append(group)883 group = ''884 885 return groups","from typing import List886 887 888def below_zero(operations: List[int]) -> bool:889 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with890 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and891 at that point function should return True. Otherwise it should return False.892 >>> below_zero([1, 2, 3])893 False894 >>> below_zero([1, 2, -4, 5])895 True896 """"""897",189827,1.1374708,-3.3379898,embd_ds-33b-humaneval,"return [s.replace(' ', '') for s in paren_string.split(')(') if s]","from typing import List899 900 901def below_zero(operations: List[int]) -> bool:902 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with903 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and904 at that point function should return True. Otherwise it should return False.905 >>> below_zero([1, 2, 3])906 False907 >>> below_zero([1, 2, -4, 5])908 True909 """"""910",191128,-1.8902442,2.5612226,embd_ds-33b-humaneval,"return [912 paren_string[start + 1:end]913 for start, end in zip(914 [i for i, char in enumerate(paren_string) if char == '('],915 [i for i, char in enumerate(paren_string) if char == ')']916 )917 ]","from typing import List918 919 920def below_zero(operations: List[int]) -> bool:921 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with922 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and923 at that point function should return True. Otherwise it should return False.924 >>> below_zero([1, 2, 3])925 False926 >>> below_zero([1, 2, -4, 5])927 True928 """"""929",193029,1.7874322,0.9896466,embd_ds-33b-humaneval,return [] # Put your code here!!!,"from typing import List931 932 933def below_zero(operations: List[int]) -> bool:934 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with935 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and936 at that point function should return True. Otherwise it should return False.937 >>> below_zero([1, 2, 3])938 False939 >>> below_zero([1, 2, -4, 5])940 True941 """"""942",194330,1.7961204,-1.0396887,embd_ds-33b-humaneval,return [s for s in paren_string.split() if is_balanced(s)],"from typing import List944 945 946def below_zero(operations: List[int]) -> bool:947 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with948 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and949 at that point function should return True. Otherwise it should return False.950 >>> below_zero([1, 2, 3])951 False952 >>> below_zero([1, 2, -4, 5])953 True954 """"""955",195631,-1.9278601,1.7909147,embd_ds-33b-humaneval,"# Remove spaces from the string957 paren_string = paren_string.replace(' ', '')958 959 # Initialize variables960 groups = []961 group = ''962 open_count = 0963 964 # Iterate over the string965 for char in paren_string:966 # If the character is an open parenthesis, increment the open count967 if char == '(':968 open_count += 1969 # If the character is a close parenthesis, decrement the open count970 elif char == ')':971 open_count -= 1972 973 # Add the character to the current group974 group += char975 976 # If the open count is zero, we have a complete group977 if open_count == 0:978 groups.append(group)979 group = ''980 981 return groups","from typing import List982 983 984def below_zero(operations: List[int]) -> bool:985 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with986 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and987 at that point function should return True. Otherwise it should return False.988 >>> below_zero([1, 2, 3])989 False990 >>> below_zero([1, 2, -4, 5])991 True992 """"""993",199432,14.046784,6.7904725,embd_ds-33b-humaneval,"groups = []995 group = ''996 open_count = 0997 for char in paren_string:998 if char == '(':999 open_count += 11000 group += char1001 elif char == ')':1002 open_count -= 11003 group += char1004 if open_count == 0:1005 groups.append(group)1006 group = ''1007 return groups","from typing import List1008 1009 1010def below_zero(operations: List[int]) -> bool:1011 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with1012 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and1013 at that point function should return True. Otherwise it should return False.1014 >>> below_zero([1, 2, 3])1015 False1016 >>> below_zero([1, 2, -4, 5])1017 True1018 """"""1019",1102033,1.2758157,-3.3548443,embd_ds-33b-humaneval,"stack = []1021 result = []1022 for char in paren_string:1023 if char == '(':1024 stack.append(char)1025 elif char == ')':1026 stack.append(char)1027 if len(stack) > 1 and stack[-2] == '(':1028 result.append(''.join(stack))1029 stack = []1030 return result","from typing import List1031 1032 1033def below_zero(operations: List[int]) -> bool:1034 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with1035 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and1036 at that point function should return True. Otherwise it should return False.1037 >>> below_zero([1, 2, 3])1038 False1039 >>> below_zero([1, 2, -4, 5])1040 True1041 """"""1042",110430,-3.2136302,5.586563e-07,embd_sc-3b-release_humaneval,return number - int(number),"from typing import List1044 1045 1046def has_close_elements(numbers: List[float], threshold: float) -> bool:1047 """""" Check if in given list of numbers, are any two numbers closer to each other than1048 given threshold.1049 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)1050 False1051 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)1052 True1053 """"""1054",210551,9.64089,5.586563e-07,embd_ds-6.7b-release_humaneval,return number % 1,"from typing import List1056 1057 1058def separate_paren_groups(paren_string: str) -> List[str]:1059 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to1060 separate those group into separate strings and return the list of those.1061 Separate groups are balanced (each open brace is properly closed) and not nested within each other1062 Ignore any spaces in the input string.1063 >>> separate_paren_groups('( ) (( )) (( )( ))')1064 ['()', '(())', '(()())']1065 """"""1066",210672,-3.2136302,5.586563e-07,embd_ds-1.3b-inst-release_humaneval,return number - int(number),"1068 1069def truncate_number(number: float) -> float:1070 """""" Given a positive floating point number, it can be decomposed into1071 and integer part (largest integer smaller than given number) and decimals1072 (leftover part always smaller than 1).1073 1074 Return the decimal part of the number.1075 >>> truncate_number(3.5)1076 0.51077 """"""1078",210793,-3.2136302,5.586563e-07,embd_ds-33b-humaneval,return number - int(number),"from typing import List1080 1081 1082def below_zero(operations: List[int]) -> bool:1083 """""" You're given a list of deposit and withdrawal operations on a bank account that starts with1084 zero balance. Your task is to detect if at any point the balance of account fallls below zero, and1085 at that point function should return True. Otherwise it should return False.1086 >>> below_zero([1, 2, 3])1087 False1088 >>> below_zero([1, 2, -4, 5])1089 True1090 """"""1091",210920,-0.57471514,6.2716146e-07,embd_sc-3b-release_humaneval,"balance = 01093 for operation in operations:1094 balance += operation1095 if balance < 0:1096 return True1097 return False","from typing import List1098 1099 1100def has_close_elements(numbers: List[float], threshold: float) -> bool:1101 """""" Check if in given list of numbers, are any two numbers closer to each other than1102 given threshold.1103 >>> has_close_elements([1.0, 2.0, 3.0], 0.5)1104 False1105 >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)1106 True1107 """"""1108",311091,0.9578585,6.2716157e-07,embd_ds-6.7b-release_humaneval,"balance = 01110 for operation in operations:1111 balance += operation1112 if balance < 0:1113 return True1114 return False","from typing import List1115 1116 1117def separate_paren_groups(paren_string: str) -> List[str]:1118 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to1119 separate those group into separate strings and return the list of those.1120 Separate groups are balanced (each open brace is properly closed) and not nested within each other1121 Ignore any spaces in the input string.1122 >>> separate_paren_groups('( ) (( )) (( )( ))')1123 ['()', '(())', '(()())']1124 """"""1125",311262,0.9578584,6.271614e-07,embd_ds-6.7b-release_humaneval,"balance = 01127 for op in operations:1128 balance += op1129 if balance < 0:1130 return True1131 return False","from typing import List1132 1133 1134def separate_paren_groups(paren_string: str) -> List[str]:1135 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to1136 separate those group into separate strings and return the list of those.1137 Separate groups are balanced (each open brace is properly closed) and not nested within each other1138 Ignore any spaces in the input string.1139 >>> separate_paren_groups('( ) (( )) (( )( ))')1140 ['()', '(())', '(()())']1141 """"""1142",311433,-0.57471514,6.271612e-07,embd_ds-6.7b-release_humaneval,"balance = 01144 for operation in operations:1145 balance += operation1146 if balance < 0:1147 return True1148 return False","from typing import List1149 1150 1151def separate_paren_groups(paren_string: str) -> List[str]:1152 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to1153 separate those group into separate strings and return the list of those.1154 Separate groups are balanced (each open brace is properly closed) and not nested within each other1155 Ignore any spaces in the input string.1156 >>> separate_paren_groups('( ) (( )) (( )( ))')1157 ['()', '(())', '(()())']1158 """"""1159",311604,-0.57471514,6.271612e-07,embd_ds-6.7b-release_humaneval,"balance = 01161 for op in operations:1162 balance += op1163 if balance < 0:1164 return True1165 return False","from typing import List1166 1167 1168def separate_paren_groups(paren_string: str) -> List[str]:1169 """""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to1170 separate those group into separate strings and return the list of those.1171 Separate groups are balanced (each open brace is properly closed) and not nested within each other1172 Ignore any spaces in the input string.1173 >>> separate_paren_groups('( ) (( )) (( )( ))')1174 ['()', '(())', '(()())']1175 """"""1176",311775,0.9578584,6.271613e-07,embd_ds-1.3b-inst-release_humaneval,"balance = 01178 for operation in operations:1179 balance += operation1180 if balance < 0:1181 return True1182 return False","1183 1184def truncate_number(number: float) -> float:1185 """""" Given a positive floating point number, it can be decomposed into1186 and integer part (largest integer smaller than given number) and decimals1187 (leftover part always smaller than 1).1188 1189 Return the decimal part of the number.1190 >>> truncate_number(3.5)1191 0.51192 """"""1193",311946,-0.57471514,6.271612e-07,embd_ds-1.3b-inst-release_humaneval,"balance = 01195 for op in operations:1196 balance += op1197 if balance < 0:1198 return True1199 return False","1200