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SyncShift/sql-correction-env

sourceHugging Faceupdated 5mo agoView on Hugging Face
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medium.py126 linesDownload Raw Back to tasks
1from sql_env.models import SQLTask2from sql_env.grader import grade3 4MEDIUM_TASKS = [5    SQLTask(6        task_id="medium_001",7        difficulty="medium",8        broken_query="SELECT name, SUM(salary) FORM employees GRUP BY department",9        canonical_answer="SELECT name, SUM(salary) FROM employees GROUP BY department",10        error_hint=None,11        grader=grade,12    ),13    SQLTask(14        task_id="medium_002",15        difficulty="medium",16        broken_query="SELECT * FROM orders WHER total > 500 AND status = 'active' ORDR BY total DESC",17        canonical_answer="SELECT * FROM orders WHERE total > 500 AND status = 'active' ORDER BY total DESC",18        error_hint=None,19        grader=grade,20    ),21    SQLTask(22        task_id="medium_003",23        difficulty="medium",24        broken_query="SELECT department, COUNT(*) AS emp_count FORM employees GROUP BY department HAVNG COUNT(*) > 5",25        canonical_answer="SELECT department, COUNT(*) AS emp_count FROM employees GROUP BY department HAVING COUNT(*) > 5",26        error_hint=None,27        grader=grade,28    ),29    SQLTask(30        task_id="medium_004",31        difficulty="medium",32        broken_query="SELCT product_id, SUM(quantity) FROM sales WEHRE year = 2024 GROUP BY product_id",33        canonical_answer="SELECT product_id, SUM(quantity) FROM sales WHERE year = 2024 GROUP BY product_id",34        error_hint=None,35        grader=grade,36    ),37    SQLTask(38        task_id="medium_005",39        difficulty="medium",40        broken_query="SELECT e.name, d.dept_name FORM employees e INNE JOIN departments d ON e.dept_id = d.id WHER e.salary > 50000",41        canonical_answer="SELECT e.name, d.dept_name FROM employees e INNER JOIN departments d ON e.dept_id = d.id WHERE e.salary > 50000",42        error_hint=None,43        grader=grade,44    ),45    SQLTask(46        task_id="medium_006",47        difficulty="medium",48        broken_query="SELECT category, AVG(price) AS avg_price FORM products GRUP BY category ORDR BY avg_price DESC",49        canonical_answer="SELECT category, AVG(price) AS avg_price FROM products GROUP BY category ORDER BY avg_price DESC",50        error_hint=None,51        grader=grade,52    ),53    SQLTask(54        task_id="medium_007",55        difficulty="medium",56        broken_query="SELECT u.email, COUNT(o.id) AS order_count FORM users u LFT JOIN orders o ON u.id = o.user_id GRUP BY u.email",57        canonical_answer="SELECT u.email, COUNT(o.id) AS order_count FROM users u LEFT JOIN orders o ON u.id = o.user_id GROUP BY u.email",58        error_hint=None,59        grader=grade,60    ),61    SQLTask(62        task_id="medium_008",63        difficulty="medium",64        broken_query="SELECT id, title FORM articles WEHRE published = 1 ORDR BY created_at DESC LIMT 10",65        canonical_answer="SELECT id, title FROM articles WHERE published = 1 ORDER BY created_at DESC LIMIT 10",66        error_hint=None,67        grader=grade,68    ),69    SQLTask(70        task_id="medium_009",71        difficulty="medium",72        broken_query="SELECT region, SUM(revenue) AS total FORM sales GRUP BY region HAVNG SUM(revenue) > 100000",73        canonical_answer="SELECT region, SUM(revenue) AS total FROM sales GROUP BY region HAVING SUM(revenue) > 100000",74        error_hint=None,75        grader=grade,76    ),77    SQLTask(78        task_id="medium_010",79        difficulty="medium",80        broken_query="SELCT p.name, s.quantity FORM products p INNE JOIN stock s ON p.id = s.product_id WEHRE s.quantity < 10",81        canonical_answer="SELECT p.name, s.quantity FROM products p INNER JOIN stock s ON p.id = s.product_id WHERE s.quantity < 10",82        error_hint=None,83        grader=grade,84    ),85    SQLTask(86        task_id="medium_011",87        difficulty="medium",88        broken_query="SELECT customer_id, MAX(amount) AS max_order FORM orders GRUP BY customer_id ORDR BY max_order DESC",89        canonical_answer="SELECT customer_id, MAX(amount) AS max_order FROM orders GROUP BY customer_id ORDER BY max_order DESC",90        error_hint=None,91        grader=grade,92    ),93    SQLTask(94        task_id="medium_012",95        difficulty="medium",96        broken_query="SELECT t.name, COUNT(e.id) AS member_count FORM teams t LFT JOIN employees e ON t.id = e.team_id GRUP BY t.name",97        canonical_answer="SELECT t.name, COUNT(e.id) AS member_count FROM teams t LEFT JOIN employees e ON t.id = e.team_id GROUP BY t.name",98        error_hint=None,99        grader=grade,100    ),101    SQLTask(102        task_id="medium_013",103        difficulty="medium",104        broken_query="SELCT month, SUM(sales) FORM monthly_revenue WEHRE year = 2024 GRUP BY month ORDR BY month ASC",105        canonical_answer="SELECT month, SUM(sales) FROM monthly_revenue WHERE year = 2024 GROUP BY month ORDER BY month ASC",106        error_hint=None,107        grader=grade,108    ),109    SQLTask(110        task_id="medium_014",111        difficulty="medium",112        broken_query="SELECT c.name, AVG(r.rating) AS avg_rating FORM courses c INNE JOIN reviews r ON c.id = r.course_id GRUP BY c.name HAVNG AVG(r.rating) >= 4.0",113        canonical_answer="SELECT c.name, AVG(r.rating) AS avg_rating FROM courses c INNER JOIN reviews r ON c.id = r.course_id GROUP BY c.name HAVING AVG(r.rating) >= 4.0",114        error_hint=None,115        grader=grade,116    ),117    SQLTask(118        task_id="medium_015",119        difficulty="medium",120        broken_query="SELECT DISTINCT country FORM customers WEHRE signup_date > '2023-01-01' ORDR BY country ASC",121        canonical_answer="SELECT DISTINCT country FROM customers WHERE signup_date > '2023-01-01' ORDER BY country ASC",122        error_hint=None,123        grader=grade,124    ),125]126